MT480 · Unit 2

MT480 Unit 2 time value problem set example

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Six decisions at a composite greenhouse grower fill this MT480 Unit 2 problem set, each drawn on a dated timeline before any formula appears. A seed license, a leased growing range, a supplier's early-payment discount, an LED retrofit loan, a new glass phase that earns nothing for two years and a balloon loan on a packing robot move money forward and back.

What this page holds

Timelines first, formulas second: six worked problems for MT480 Unit 2, from a 23.45 percent trade-credit cost to a deferred glasshouse annuity worth 28.09 million today. Searches like "mt 480 unit 2 assignment example", "mt480 unit 2 sample" and "mt480 unit 2 example" land here.

What a finished MT480 Unit 2 time value problem set looks like

Roughly five pages hold six problems, each opening with its timeline. Paying 1.46 million for a tomato variety license in three years beats 1.20 million today by 8,205 dollars at 7 percent. Rent of 312,000 per quarter paid in advance for six years is worth 6,019,168 at 2 percent a quarter, 118,023 more than the same payments in arrears. Skipping a 2/10 net 45 discount from a packaging supplier costs 23.45 percent a year, so the grower should borrow on its 8.25 percent line and pay early. Monthly savings of 61,000 retire a 4.35 million LED loan at 6.6 percent in 90.78 months. A glass phase paying 5.2 million a year for ten years after a two-year build is worth 28,088,393 today. A 2.8 million robot loan with a 560,000 balloon closes the set at 37,387.03 a month.

How a MT480 Unit 2 example is structured

Problems follow the complexity of their timelines rather than their dollar size. The license comparison opens because it involves only two points on one line. The rent follows, since an annuity due is the ordinary annuity shifted one period, and the sample shows that shift as a multiplication by 1.02. The discount problem converts a 35-day gap into an effective annual rate, the one place in the set where compounding frequency could change the decision. The retrofit loan is solved for time rather than money, using logarithms and then checked with the NPER function. The glass phase is valued in two moves, an annuity to year two and a single discount back to today. The balloon loan subtracts the balloon's present value, 338,811, before solving for the payment. Every problem ends on a sentence naming the choice its figure supports.

Two points on one line

The license problem needs only a present value of 1,191,795 set against a 1.20 million price, yet its timeline still marks today as zero and the deferred payment at year three.

Rent paid in advance

Quarterly rent due on the first day of each quarter makes the annuity due worth 2 percent more than ordinary payments, 118,023 dollars across twenty-four quarters.

The price of skipping a discount

Forgoing 2 percent to hold cash 35 extra days compounds to 23.45 percent a year, against 21.28 percent on the simple formula often quoted in its place.

Solving for months

Setting 61,000 a month against a 4.35 million balance at 0.55 percent monthly gives 90.78 payments, roughly seven years and seven months of electricity savings.

Two years of nothing

Discounting the 33.37 million value at year two back to today costs 5.28 million, the price of waiting while glass is built, planted and brought into production.

A balloon lowers the payment

The 560,000 final payment trims the monthly amount from 42,533.78 to 37,387.03 but raises total interest over seven years from 772,838 to 900,510.

Where marks go in MT480 Unit 2

Timing conventions carry most of the points in a set like this one. Rent paid in advance but valued as an ordinary annuity misses by 118,023 dollars, and a grader can read the error from the size of the gap alone. Trade-credit costs quoted from the simple formula understate the effective rate by about two points; here that does not reverse the decision, though with a cheaper credit line it would. A balloon ignored when solving the robot loan produces 42,533.78, a figure that exposes the omission at a glance. In the glasshouse problem, the usual slip is discounting the year-two value back three years instead of two, because the first payment falls in year three. Answers without a closing decision sentence forfeit interpretation credit even when each figure is correct.

Get a MT480 Unit 2 example written to your instructions

Paste the Unit 2 problems exactly as issued, with any rule on calculators, tables or spreadsheet functions, plus the rubric. A custom set draws each timeline before solving, shows the formula with numbers substituted and ends every answer on the decision it supports. There is no charge for your first custom sample, typically delivered in 24-48h.

MT480 Unit 2 questions, answered

Why draw a timeline for a one-step problem?

Because one-step problems are where timing slips go unnoticed. A timeline fixes which period is zero, whether a payment falls at the start or end of each period, and which direction money moves. In the sample, the license and rent problems look trivial until the timeline shows one payment in year three and twenty-four payments starting today, which changes the formula chosen.

Should the trade-credit cost use the simple or effective formula?

The effective formula, unless your section specifies otherwise, since it compounds the 2 percent over roughly 10.4 periods a year the way a lender would. The sample shows both, 21.28 and 23.45 percent, and explains that either exceeds the 8.25 percent credit line, so the decision holds regardless. The gap between formulas matters more when borrowing costs sit closer to the discount's price.

Does the sample show spreadsheet functions?

Yes, beside each hand calculation: PV with its type argument set to 1 for the rent paid in advance, NPER for the retrofit loan, and PMT with a future value entered for the balloon. Instructors often still want the formula and inputs visible so partial credit remains possible. If your section requires calculator keystrokes instead, the custom version shows those.