Sodium intake from a 36-person workplace screening, estimated as a 95 percent t interval and read for what its width permits, is the HS345 Unit 6 confidence interval problem shown here. Searches like "hs 345 unit 6 assignment example", "hs345 unit 6 sample" and "hs345 unit 6 example" land here.
What a finished HS345 Unit 6 confidence interval problem looks like
Four compact parts make up the solution. Part A lays out the inputs in a small table: sample size 36, mean 3,180 milligrams, standard deviation 920, standard error 153.3, and a t value of 2.030 on 35 degrees of freedom. Part B builds the 95 percent interval, 2,869 to 3,491 milligrams, and sets it against the 2,300-milligram daily limit in the Dietary Guidelines for Americans, which lies below the entire range. Part C repeats the interval at 90 and 99 percent, giving widths of about 518 and 835 milligrams, so the price of extra confidence is visible. Part D asks how many employees a future screening would need for a margin of 150 milligrams, and answers about 145. A short paragraph on recall data closes the solution.
How a HS345 Unit 6 example is structured
Each part answers a question the wellness committee might ask, in the order it would arise. Inputs come first so that every later number can be traced, and the choice of t over z is justified in one sentence: the population standard deviation is unknown and the sample is modest. The interval follows, then its interpretation, worded as a statement about the method's long-run success rather than a 95 percent chance attached to this one range. Comparison with the guideline limit comes next because it is the reason anyone collected the data. The three confidence levels are placed after the main answer, so they read as a lesson about width. Sample size planning follows from width. The closing paragraph notes that one-day recalls miss variation between days and that self-reported sodium tends to run low, so the interval is precise about recalls rather than habits.
Inputs in one table
Sample size, mean, standard deviation, standard error and critical value in five rows, with the degrees of freedom printed beside the t value.
A range, not a point
From 2,869 to 3,491 milligrams at 95 percent. The wording describes the procedure capturing the true mean in the long run, the phrasing graders look for.
Against the guideline limit
The 2,300-milligram limit sits almost 570 milligrams below the lower end, so the committee can say typical intake in this workforce exceeds it without overstating by how much.
What extra confidence costs
Ninety, 95 and 99 percent intervals side by side. Wider confidence buys a longer range, and the table shows the trade in milligrams.
Planning a sharper estimate
About 145 employees would bring the margin to 150 milligrams; halving it again would take roughly four times as many. The quadrupling rule is stated plainly.
Where marks go in HS345 Unit 6
Inputs, the critical value, the wording of the interpretation and a conclusion tied to the question make up the usual rows on an HS345 interval problem. The critical value row trips many submissions, which use 1.96 for a sample of 36 with an estimated standard deviation; the numerical gap is small here, but the reasoning earns the point. Interpretation carries real weight. Claiming a 95 percent chance that this particular range contains the population mean is marked down in most sections, while wording about the method's long-run capture rate is credited. Conclusion credit goes to comparing the range with the 2,300 limit. Further deductions follow intervals given without units, margins of error confused with the full width, sample sizes rounded down instead of up, and a closing claim about salt stated as fact about each employee.
Get a HS345 Unit 6 example written to your instructions
Share the numbers your HS345 Unit 6 problem gives, whether a mean, a proportion or raw data, together with its instructions and rubric. A free first custom sample, ready in 24-48 hours, builds the interval with the right critical value, words the interpretation the way graders credit, and explains what the range's width allows anyone to conclude.
HS345 Unit 6 questions, answered
Why a t value instead of 1.96?
Because the standard deviation of 920 comes from the sample, not from a known population. The t distribution widens the interval slightly to account for that extra uncertainty, and with 35 degrees of freedom its critical value is 2.030. The difference from 1.96 is modest at this sample size but grows quickly in smaller samples.
Does the interval mean 95 percent of employees eat between 2,869 and 3,491 milligrams?
No, and that misreading is common. The interval describes the average intake of the workforce, not individuals. Individual intakes vary far more, as the standard deviation of 920 shows. A range covering most individuals would be a different calculation entirely, and the example flags the difference in a sentence near the end.
What if my problem gives a proportion instead of a mean?
The structure stays the same: inputs, standard error, critical value, interval, interpretation and comparison with a benchmark. The standard error formula changes to one based on the sample proportion, and the course may ask for a check that successes and failures are both large enough. A custom sample follows whichever form your prompt uses.